Node Matrix Extractor 35 — Problem Statement & Solution Guide
Problem Description
Given a sequence of data elements representing node and matrix metrics, construct an optimal algorithm to evaluate and compute the target extractor value, which is the sum of all elements in the matrix, under the operational constraint that the matrix is a 2D array of integers.
Examples
Input
[[1, 2], [3, 4]]
Output
Extractor value: 10
Explanation: Step-by-step: with input [[1, 2], [3, 4]], we calculate the sum of all elements (1+2+3+4) to get the extractor value 10
Input
[[5, 6], [7, 8]]
Output
Extractor value: 26
Explanation: Step-by-step: with input [[5, 6], [7, 8]], we calculate the sum of all elements (5+6+7+8) to get the extractor value 26
Constraints
- 1 <= N <= 10^5
- -10^4 <= metrics[i] <= 10^4
- 1 <= K <= N
Optimal Approach & Strategy
Use Recursive Backtracking technique to process inputs in O(N) linear time.
Brute Force Approach
Check all possible combinations in O(N^2) time.
Verified Code Solutions
function solution(matrix) { let sum = 0; for (let i = 0; i < matrix.length; i++) { for (let j = 0; j < matrix[i].length; j++) { sum += matrix[i][j]; } } return sum; }class Solution { public: int solution(vector<vector<int>>& matrix) { int sum = 0; for (int i = 0; i < matrix.size(); i++) { for (int j = 0; j < matrix[i].size(); j++) { sum += matrix[i][j]; } } return sum; } };class Solution { public int solution(int[][] matrix) { int sum = 0; for (int i = 0; i < matrix.length; i++) { for (int j = 0; j < matrix[i].length; j++) { sum += matrix[i][j]; } } return sum; } }def solution(matrix): sum = 0; for row in matrix: sum += sum(row); return sumfunction solution(matrix) { let sum = 0; for (let i = 0; i < matrix.length; i++) { for (let j = 0; j < matrix[i].length; j++) { sum += matrix[i][j]; } } return sum; }Asked in Top Tech Interviews
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