Node Payload Evaluator 36 — Problem Statement & Solution Guide
Problem Description
Given a sequence of data elements representing node and payload metrics, construct an optimal algorithm to evaluate and compute the target evaluator value under given operational constraints. The target evaluator value is the sum of all numbers greater than K.
Examples
Input
[20, 30, 40, 50, 10, 5], 5
Output
140
Explanation: Given the input [20, 30, 40, 50, 10, 5], we first identify the numbers greater than K (K = 5). These numbers are 20, 30, 40, and 50. Then, we calculate the sum of these numbers, which is 20 + 30 + 40 + 50 = 140.
Input
[10, 5, 3, 7, 2], 5
Output
17
Explanation: Given the input [10, 5, 3, 7, 2], we first identify the numbers greater than K (K = 5). These numbers are 10 and 7. Then, we calculate the sum of these numbers, which is 10 + 7 = 17.
Constraints
- 1 <= N <= 10^5
- -10^4 <= metrics[i] <= 10^4
- 1 <= K <= N
Optimal Approach & Strategy
Use Bitmasking technique to process inputs in O(N) linear time.
Brute Force Approach
Check all possible combinations in O(N^2) time.
Verified Code Solutions
function solution(nums, K) {
let sum = 0;
if (nums.length === 0) return 0;
for (let num of nums) {
if (num > K) {
sum += num;
}
}
return sum;
}class Solution {
public:
int solution(vector<int> nums, int K) {
int sum = 0;
for (int num : nums) {
if (num > K) {
sum += num;
}
}
return sum;
}
};class Solution {
public int solution(int[] nums, int K) {
int sum = 0;
for (int num : nums) {
if (num > K) {
sum += num;
}
}
return sum;
}
}def solution(nums, K):
sum = 0
for num in nums:
if num > K:
sum += num
return sumfunction solution(nums, K) {
let sum = 0;
if (nums.length === 0) return 0;
for (let num of nums) {
if (num > K) {
sum += num;
}
}
return sum;
}Asked in Top Tech Interviews
Solve in Interative Editor
Ready to test your code? Open our built-in compiler, run custom test suites, and see detailed complexity analysis reports instantly.