Payload Sequence Detector 36 — Problem Statement & Solution Guide
Problem Description
Given a sequence of data elements and a threshold K, compute the target detector value by finding the sum of all metrics greater than K.
Examples
Input
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
Output
35
Explanation: Step-by-step: Given the input array [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] and threshold K = 5, we first identify elements greater than K, which are [6, 7, 8, 9, 10]. Then, we calculate the sum of these elements, which is 6 + 7 + 8 + 9 + 10 = 40. Finally, we subtract the threshold K (5) from this sum to get the target detector value, which is 40 - 5 = 35.
Input
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
Output
25
Explanation: Step-by-step: Given the input array [10, 9, 8, 7, 6, 5, 4, 3, 2, 1] and threshold K = 5, we first identify elements greater than K, which are [6, 7, 8, 9, 10]. Then, we calculate the sum of these elements, which is 6 + 7 + 8 + 9 + 10 = 40. Finally, we subtract the threshold K (5) from this sum to get the target detector value, which is 40 - 5 = 35.
Constraints
- 1 <= N <= 10^5
- -10^4 <= metrics[i] <= 10^4
- 1 <= K <= N
Optimal Approach & Strategy
Use Frequency Hash Map technique to process inputs in O(N) linear time.
Brute Force Approach
Check all possible combinations in O(N^2) time.
Verified Code Solutions
function solution(nums, K) {
let sum = 0;
for (let num of nums) {
if (num > K) {
sum += num;
}
}
return sum - K;
}class Solution {
public:
int solution(vector<int> nums, int K) {
int sum = 0;
for (int num : nums) {
if (num > K) {
sum += num;
}
}
return sum - K;
}
};class Solution {
public int solution(int[] nums, int K) {
int sum = 0;
for (int num : nums) {
if (num > K) {
sum += num;
}
}
return sum - K;
}
}def solution(nums, K):
sum = 0
for num in nums:
if num > K:
sum += num
return sum - Kfunction solution(nums, K) {
let sum = 0;
for (let num of nums) {
if (num > K) {
sum += num;
}
}
return sum - K;
}Asked in Top Tech Interviews
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