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Sensor Checkpoint Resolver 35 Solution

Problem Statement

Given a sequence of data elements representing sensor and checkpoint metrics, and an integer K, construct an optimal algorithm to compute the sum of all elements greater than K.

Example 1
Input
[1, 2, 3, 4, 5], K = 3
Output
9

Explanation: Step-by-step: with input [1, 2, 3, 4, 5] and K = 3, we filter elements greater than K (4 and 5), then sum them up, giving output 9

Example 2
Input
[10, 20, 30, 40, 50], K = 25
Output
120

Explanation: Step-by-step: with input [10, 20, 30, 40, 50] and K = 25, we filter elements greater than K (30, 40, 50), then sum them up, giving output 120

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N
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Sensor Checkpoint Resolver 35 — Problem Statement & Solution Guide

QueueMediumFrequency Hash Map
TimeO(n)
|
SpaceO(n)

Problem Description

Given a sequence of data elements representing sensor and checkpoint metrics, and an integer K, construct an optimal algorithm to compute the sum of all elements greater than K.

Examples

Example 1

Input

[1, 2, 3, 4, 5], K = 3

Output

9

Explanation: Step-by-step: with input [1, 2, 3, 4, 5] and K = 3, we filter elements greater than K (4 and 5), then sum them up, giving output 9

Example 2

Input

[10, 20, 30, 40, 50], K = 25

Output

120

Explanation: Step-by-step: with input [10, 20, 30, 40, 50] and K = 25, we filter elements greater than K (30, 40, 50), then sum them up, giving output 120

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N

Optimal Approach & Strategy

Use Frequency Hash Map technique to process inputs in O(N) linear time.

Brute Force Approach

Check all possible combinations in O(N^2) time.

Verified Code Solutions

JavaScript Solution
Time: O(n)
function solution(nums, K) { return nums.filter(num => num > K).reduce((a, b) => a + b, 0); }

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