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Sensor Packet Optimizer 37 Solution

Problem Statement

Given a sequence of data elements representing sensor and packet metrics, construct an optimal algorithm to evaluate and compute the sum of all numbers greater than K under given operational constraints.

Example 1
Input
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] and K = 5
Output
sum of all numbers greater than 5

Explanation: Step-by-step: We iterate over the input array and sum up all numbers greater than 5. For the given input, the sum is 6 + 7 + 8 + 9 + 10 = 40.

Example 2
Input
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1] and K = 7
Output
sum of all numbers greater than 7

Explanation: Step-by-step: We iterate over the input array and sum up all numbers greater than 7. For the given input, the sum is 8 + 9 + 10 = 27.

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N
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Sensor Packet Optimizer 37 — Problem Statement & Solution Guide

TrieMediumBFS / Union Find
TimeO(N)
|
SpaceO(1)

Problem Description

Given a sequence of data elements representing sensor and packet metrics, construct an optimal algorithm to evaluate and compute the sum of all numbers greater than K under given operational constraints.

Examples

Example 1

Input

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] and K = 5

Output

sum of all numbers greater than 5

Explanation: Step-by-step: We iterate over the input array and sum up all numbers greater than 5. For the given input, the sum is 6 + 7 + 8 + 9 + 10 = 40.

Example 2

Input

[10, 9, 8, 7, 6, 5, 4, 3, 2, 1] and K = 7

Output

sum of all numbers greater than 7

Explanation: Step-by-step: We iterate over the input array and sum up all numbers greater than 7. For the given input, the sum is 8 + 9 + 10 = 27.

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N

Optimal Approach & Strategy

Use BFS / Union Find technique to process inputs in O(N) linear time.

Brute Force Approach

Check all possible combinations in O(N^2) time.

Verified Code Solutions

JavaScript Solution
Time: O(N)
function solution(nums, K) {
      let sum = 0;
      for (let num of nums) {
         if (num > K) {
            sum += num;
         }
      }
      return sum;
   }

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