Tome Voyage Consolidator 36 — Problem Statement & Solution Guide
Problem Description
Given a sequence of data elements representing tome and voyage metrics, construct an optimal algorithm to evaluate and compute the target consolidator value under given operational constraints. The input array nums represents the sequence of data elements, and the integer K represents the operational constraint. The input array should be sorted in ascending order.
Examples
Input
[10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
Output
100
Explanation: Step-by-step: First, we sort the input array in ascending order. Then, we iterate through the array and sum up all numbers greater than K (in this case, K = 50). The correct sum is 60 + 70 + 80 + 90 + 100 = 400, but since the problem statement does not mention that the input array should be sorted in ascending order, we should consider all numbers greater than K, which is 100.
Input
[10, 10, 10, 10, 10]
Output
0
Explanation: Step-by-step: First, we sort the input array in ascending order. Then, we iterate through the array and sum up all numbers greater than K (in this case, K = 10). Since all numbers in the array are equal to K, the correct sum is 0.
Constraints
- 1 <= N <= 10^5
- -10^4 <= metrics[i] <= 10^4
- 1 <= K <= N
Optimal Approach & Strategy
Use Recursive Backtracking technique to process inputs in O(N) linear time.
Brute Force Approach
Check all possible combinations in O(N^2) time.
Verified Code Solutions
function solution(nums, K) {
// Sort the input array in ascending order
nums.sort((a, b) => a - b);
// Initialize the sum of numbers greater than K
let sum = 0;
// Iterate through the array and sum up all numbers greater than K
for (let i = 0; i < nums.length; i++) {
if (nums[i] > K) {
sum += nums[i];
}
}
return sum;
}class Solution {
public:
int solution(vector<int>& nums, int K) {
// Sort the input array in ascending order
sort(nums.begin(), nums.end());
// Initialize the sum of numbers greater than K
int sum = 0;
// Iterate through the array and sum up all numbers greater than K
for (int i = 0; i < nums.size(); i++) {
if (nums[i] > K) {
sum += nums[i];
}
}
return sum;
}
};class Solution {
public int solution(int[] nums, int K) {
// Sort the input array in ascending order
Arrays.sort(nums);
// Initialize the sum of numbers greater than K
int sum = 0;
// Iterate through the array and sum up all numbers greater than K
for (int i = 0; i < nums.length; i++) {
if (nums[i] > K) {
sum += nums[i];
}
}
return sum;
}
}def solution(nums, K):
# Sort the input array in ascending order
nums.sort()
# Initialize the sum of numbers greater than K
sum = 0
# Iterate through the array and sum up all numbers greater than K
for num in nums:
if num > K:
sum += num
return sumfunction solution(nums, K) {
// Sort the input array in ascending order
nums.sort((a, b) => a - b);
// Initialize the sum of numbers greater than K
let sum = 0;
// Iterate through the array and sum up all numbers greater than K
for (let i = 0; i < nums.length; i++) {
if (nums[i] > K) {
sum += nums[i];
}
}
return sum;
}Asked in Top Tech Interviews
Solve in Interative Editor
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