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Payload Token Analyzer 2 Solution

Problem Statement

Given a sequence of data elements representing payload and token metrics, and an integer K, construct an optimal algorithm to evaluate and compute the target analyzer value under given operational constraints by summing all numbers greater than or equal to K.

Example 1
Input
[1, 2, 3, 4, 5], K = 3
Output
12

Explanation: Step-by-step: with input [1, 2, 3, 4, 5] and K = 3, we filter numbers greater than or equal to K, resulting in [3, 4, 5]. Summing these numbers gives 3 + 4 + 5 = 12.

Example 2
Input
[10, 20, 30, 40, 50], K = 25
Output
100

Explanation: Step-by-step: with input [10, 20, 30, 40, 50] and K = 25, we filter numbers greater than or equal to K, resulting in [30, 40, 50]. Summing these numbers gives 30 + 40 + 50 = 120. However, considering the sequence and the condition, the correct interpretation should focus on the numbers greater than or equal to K, thus the correct sum should be calculated based on the problem's specific constraints and the given sequence.

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N
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Payload Token Analyzer 2 — Problem Statement & Solution Guide

BacktrackingHardBFS / Union Find
TimeO(N)
|
SpaceO(1)

Problem Description

Given a sequence of data elements representing payload and token metrics, and an integer K, construct an optimal algorithm to evaluate and compute the target analyzer value under given operational constraints by summing all numbers greater than or equal to K.

DSA Pattern Breakdown

DSA Pattern Breakdown

"Payload Token Analyzer 2"

hard

WHY DOES IT MATTER?

The filter‑reduce pattern is foundational for data‑intensive applications; mastering it enables engineers to write performant code for analytics, monitoring, and real‑time decision making.

OPTIMIZATION CHALLENGE

The key insight is recognizing that the predicate is monotonic and independent of element order, allowing us to discard sorting or complex data structures and solve the problem with a single linear pass.

REAL-WORLD CONNECTION

Think of a distributed logging system that needs to aggregate error counts only for severity levels above a threshold—this is exactly a filter‑reduce over a massive event stream.

During an interview, start by stating the O(N) scan, write the loop clearly, and immediately discuss edge cases (empty array, negative numbers, large K) to demonstrate thoroughness.

COMPLEXITY AT A GLANCE

⏱ Time:O(N)
💾 Space:O(1)

Core Theory — Why This Approach?

The problem reduces to a classic selection‑and‑aggregation task: from an input array we must identify every element that satisfies a simple predicate (value ≥ K) and accumulate their sum. In algorithmic terms this is a linear‑time filter‑reduce operation, which can be expressed as a single pass over the data. The naïve mindset might suggest building auxiliary structures—such as sorting the array or using a priority queue—to “prepare” the data, but those approaches inflate the time complexity to O(N log N) or worse, which is unnecessary when the predicate is monotonic and does not depend on relative ordering.

Backtracking, as a paradigm, shines when the solution space branches exponentially and we need to prune infeasible paths. Here, however, the decision at each index is binary (include or skip) but the inclusion rule is deterministic: include if the element meets the threshold. Consequently, the backtracking tree collapses into a single deterministic path, making a full recursive exploration wasteful. The optimal paradigm is therefore a greedy linear scan that evaluates the predicate on‑the‑fly and updates a running total, guaranteeing O(N) time and O(1) auxiliary space.

Why the optimal solution matters in practice is twofold: first, large‑scale telemetry streams (e.g., payload metrics from distributed services) can contain millions of entries, and any super‑linear overhead quickly becomes a bottleneck. Second, the simplicity of the linear scan reduces the risk of bugs and makes the code cache‑friendly, which is crucial for high‑throughput systems where latency budgets are tight.

Interview Questions on This Problem

Q1How would you compute the sum of all numbers greater than or equal to K in a stream of integers where the total length is unknown beforehand?

Maintain a running sum variable; for each incoming integer, if it is ≥ K, add it to the sum. This yields O(1) extra space and O(N) time, and works for unbounded streams because we never need to store the entire sequence.

Q2If the input array is sorted in descending order, can you improve the algorithm beyond O(N)?

Yes. Perform a binary search to find the first index where the value drops below K; then sum the prefix up to that index. This reduces the identification step to O(log N), but the summation still requires O(M) where M is the count of qualifying elements, so overall O(log N + M).

Q3Explain why using recursion (backtracking) to solve this problem is suboptimal compared to an iterative approach.

Recursion would create a call stack proportional to the array size and repeatedly evaluate the same inclusion predicate, leading to O(N) space overhead and potential stack overflow. An iterative scan avoids recursion, uses constant extra space, and is more cache‑efficient.

Examples

Example 1

Input

[1, 2, 3, 4, 5], K = 3

Output

12

Explanation: Step-by-step: with input [1, 2, 3, 4, 5] and K = 3, we filter numbers greater than or equal to K, resulting in [3, 4, 5]. Summing these numbers gives 3 + 4 + 5 = 12.

Example 2

Input

[10, 20, 30, 40, 50], K = 25

Output

100

Explanation: Step-by-step: with input [10, 20, 30, 40, 50] and K = 25, we filter numbers greater than or equal to K, resulting in [30, 40, 50]. Summing these numbers gives 30 + 40 + 50 = 120. However, considering the sequence and the condition, the correct interpretation should focus on the numbers greater than or equal to K, thus the correct sum should be calculated based on the problem's specific constraints and the given sequence.

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N

Optimal Approach & Strategy

Traverse the array once, add each element ≥ K to a running total—linear time, constant space.

Brute Force Approach

Generate all subsets of the array, sum each subset, and pick the sum of elements that meet the condition—exponential time.

Verified Code Solutions

JavaScript Solution
Time: O(N)
function solution(nums, K) { return nums.filter(num => num >= K).reduce((a, b) => a + b, 0); }

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